Z^2+2z+1=2i

Solution for Z^2+2z+1=2i equation:

Simplifying
Z2 + 2z + 1 = 2i

Reorder the terms:
1 + Z2 + 2z = 2i

Solving
1 + Z2 + 2z = 2i

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + Z2 + -1 + 2z = -1 + 2i

Reorder the terms:
1 + -1 + Z2 + 2z = -1 + 2i

Combine like terms: 1 + -1 = 0
0 + Z2 + 2z = -1 + 2i
Z2 + 2z = -1 + 2i

Add '-2z' to each side of the equation.
Z2 + 2z + -2z = -1 + 2i + -2z

Combine like terms: 2z + -2z = 0
Z2 + 0 = -1 + 2i + -2z
Z2 = -1 + 2i + -2z

Simplifying
Z2 = -1 + 2i + -2z

Reorder the terms:
1 + Z2 + -2i + 2z = -1 + 2i + -2z + 1 + -2i + 2z

Reorder the terms:
1 + Z2 + -2i + 2z = -1 + 1 + 2i + -2i + -2z + 2z

Combine like terms: -1 + 1 = 0
1 + Z2 + -2i + 2z = 0 + 2i + -2i + -2z + 2z
1 + Z2 + -2i + 2z = 2i + -2i + -2z + 2z

Combine like terms: 2i + -2i = 0
1 + Z2 + -2i + 2z = 0 + -2z + 2z
1 + Z2 + -2i + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
1 + Z2 + -2i + 2z = 0

The solution to this equation could not be determined.